W=Ftriangalrcos0 which one of the following situations is an example of an object with a non-zero kinetic energy? a satellite in geosynchronous orbit which one of the following statements concerning kinetic energy is true? kinetic energy is always positive. Calculate the work that Mike does on the mower each time he pushes it 9.1 m across the yard 310 J he pushed the mower with a force of 45 N directed at an angle of 41 degrees below the horizontal direction. T= 2PI[l/g In which one of the following situations is zero net work done? a box is pulled across a rough floor at constant velocity mike is cutting the grass using a human-powered lawn mower. how much work is required to stretch the spring 0.4 m? 4 J what is the period of a pendulum consisting of a 6-kg object oscillating on a 4-m string? 4.0 s (SAME PERIOD) which one of the following statements is true concerning an object executing simple harmonic motion? The object's velocity is zero when its acceleration is a maximum a spring required a force of 5.0 N to compress it 0.1 m. What is the period of this same system on the moon where the acceleration due to gravity is roughly 1/6 that of earth? 6.0 s K=F/X A vertical block-spring system of earth has a period of 6.0 s. Calculate the spring constant for the tungsten strip. To produce a 0.25 m horizontal deflection of the block, a force of 6.5 N is required. Complete the sentence: this occurs because the angular momentum of the ball is conserved a block is suspended from the ceiling by a long, thin strip of tungsten metal. If the string is pulled down, thereby reducing the radius of the path of the ball, the speed of the ball is observed to increase. it is attached to a light string that passes through a hole in the center of the table. A ball of mass M moves in a circular path on a horizontal, frictionless surface. Which one of the following occurs as the star becomes smaller? The star's angular momentum remains constant. That's how far away the adult should be.A spinning star begins to collapse under its own gravitational pull. So we have 980 divided by 245 which gives us for so X equals four. In this case, we're probably going to need a calculator. We have 980 our ex terms cancel now to isolate our X, go ahead and divide each side by 245.
#TEETER TOTTER PHYSICS CALCULATOR PLUS#
So over on left, we now have 1 75 X plus 70 x, and that gives us 245 X and on the right. We'll choose to add 70 X to get rid of this ex term and, of course, do the same to the other side.
Now we'll go ahead and combine her ex terms. Excuse me if we still have 1 75 x and on the right, we have 70 times 14 which will go ahead and use a calculator for 70 times 14 gives us 980 and 70 times negative. So we'll go ahead and multiply that out on the right or on the left. So 14 minus X and X is the value we're looking for. We have 1 75 x equals 70 f one enough to D minus x. So we'll go ahead and plug in this information. The distance of the see saw is 14 and that gives us the information we need to solve for X. So we're gonna be looking at our lever system equation of F one X equals F to D minus X, and the important forces are F one and F two, which are 1 75 and 70. The adult weighs £175 in the child way £70 and we want to figure out how far away the child should be sitting from the fulcrum in order to balance the seesaw. We're looking at an adult and a child on a seesaw that's 14 feet long.
0 kommentar(er)
